Question: Need help with computer architecture problem. A byte-addressable main memory has a total capacity of 4 M X 32. Each word of this main memory
Need help with computer architecture problem.
A byte-addressable main memory has a total capacity of 4 M X 32. Each word of this main memory is 4 bytes. Each block of this memory is 128 words.
A. How many bytes total in this main memory?
B. How many words are in this main memory?
C. How many blocks total in this main memory?
D. Fill in the number of bis required to address Byte in each word, word in each blocks, block# in entire main memory.
bits to address/offset byte in each word =
bits to address word/offset in each blocks =
bits to address block# in entire main memory=
E. Given address ABCDF9, provide in hex the addresses/ offset shown below:
byte address/offset:
word address/offset:
block# address:
F. Draw a diagram of this main memory showing the first 2 blocks and the last 2 blocks. The first block should show at least the first and last word. The remaining blocks can be just shown as a single block. Label in hex the addresses of blocks. Lable in hex the addresses of first and last word of the first block. Label in hex all the bytes of the first word of the first block.
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