Need help with question #1 only, please be in same format as #2

1)) Find the area insider = 3 + 2cos0 and outsider = 2. 2) Find the area that is inside r = 4 sin 20 and outside r = 2 r= 4 sin Q0 r=2 O O 4 sin 20 - 2 II 2.8 A = 8 . 2 5 7 ( 4 sin 20 ) = 22 / do Sin 20 = 2 4 72 HN IF 20 = 6 =4 16 sin ?20 - 4 / do 0 = 12 N = 16 4 [4. 2 (1-60540) - Id 12 = 16 (1 - 2 000 40 ) do = 16 (8 - 2 sin40 = 16/ T- sin _ II + Sin # 4 2 = 16(7 + UB 3