Need help with second part please, keep getting marked wrong.

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. h(x) = arctan 6t dt Part 1 of 4 Let u = _. Then, du X dx - = x 7-2 Part 2 of 4 Using u = , we can write h(x) = [1/x arctan 6t dt as h(u) = arctan 6t dt. By FTC1, we have h'(u) = arctan (u) X Submit Skip (you cannot come back)