need only the correct option no need for explaination

Which statement is true about this initial value problem? 2 y' 2 7y? ,y(0) :0. O This differential equation is linear and so we cannot apply the nonlinear existence and uniqueness theorem. 0 The only solution of this problem is the trivial solution y = 0 which is consistent with the existence and uniqueness theorem of nonlinear rst order differential equations. 0 In addition to y = 0, there is another solution for this initial value problem; however this doesn't contradict the existence and uniqueness theorem of nonlinear rst order differential equations, since the continuity conditions of the theorem don't apply to this differential equation at (0, 0). Q There is another solution for this initial value problem (in addition to y = O) and this contradicts the existence and uniqueness theorem