Solve the initial value problem. y = - xet, y(0) = 1 ySolve the initial value problem. y"' = 24, y(1) = -3, y'(1) = 4 y\fThe solution of a certain differential equation is of the form y(t) = ae"+ bel, where a and b are constants. The solution has initial conditions y(0) = 3 and y' (0) - 3. Find the solution by using the initial conditions to get linear equations for a and b. y (t ) =Find the two values of k for which y(x) = ekx is a solution of the differential equation 7y' + 10y = 0. smaller value = larger value =