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need to express a part of x" + r' - 12x = sin t² answer as a convolution integral. x(0) = 1, r'(0) = 0 need to express a part of x" + r' - 12x = sin t² answer as a convolution integral. x(0) = 1, r'(0) = 0
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To express the given differential equation as a convolution integral we can use the method of undetermined coefficients Lets solve the homogeneous par... View the full answer
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