Question: Ni2+ (aq) + Ca(s) Ni(s) + Cd2+ (aq) E = +0.15 V Under standard conditions, a Ni-Cd galvanic cell generates a potential of +0.15 V

 Ni2+ (aq) + Ca(s) Ni(s) + Cd2+ (aq) E = +0.15

Ni2+ (aq) + Ca(s) Ni(s) + Cd2+ (aq) E = +0.15 V Under standard conditions, a Ni-Cd galvanic cell generates a potential of +0.15 V using the chemical reaction represented above. Which of the following best explains how [Ni+1>1 M affects the cell potential if this is the only change made to the operation of the galvanic cell? A The ratio Cd2+] Ni?+1 is smaller if (Ni2] >1 M, resulting in Q Ecell B Cd+] The ratio is smaller if (Ni2+] > 1 M, resulting in Q >1 and Ecell > Ecell [Ni] The ratio [Ni2+1 [Cd+1 is larger if [Ni2+] > 1 M, resulting in Q >1 and Ecel 1 M, resulting in Q

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