Question: No. of Observations in Sample n Factor A2 Factor D3 Factor D4 3 0 1.02 0.73 2.57 2.28 4 0 5 0.58 0 2.11 41.-

No. of Observations in Sample n Factor A2 Factor

No. of Observations in Sample n Factor A2 Factor D3 Factor D4 3 0 1.02 0.73 2.57 2.28 4 0 5 0.58 0 2.11 41.- 8 Points - Processed potatoes must meet stringent quality control standards. To meet those standards, Canada's Best needs to create three-sigma mean and range control charts for its inspection process. For those charts, the company has collected the following samples of its process output. Calculate Total for each sample, Mean of each sample, and Range of each sample to one decimal. Calculate the Average Mean and the Average Range to two decimals. Remember: n=number of observations per sample. Use the average mean and range values, along with the information in the table above, to determine the upper control limit and lower control limit for both the mean and the range control charts. Show your work as we did in all class examples and calculats all answers to bso decimal points. Left click on the formulas that are given below and edit them as needed to show your work (Just as we did in class). Sample 1 Sample 2 Sample 3 Sample 4 Mean Control Chart Equations: Observation 1 15.0 14.2 15.1 15.2 UCL = + A R = Observation 2 15.0 15.0 15.2 15.2 Observation 3 14.9 14.8 15.0 15.2 LCL = -AR= R-Chart Equations: Observation 4 15.1 15.3 15.1 15.0 Total = UCLR = D, R= LCLR = D3R = Mean (2) = In preparation for creating the quality control charts, fill in the appropriate values in the table below. Average Mean Mean Upper Control Limit Lower Control Limit = Range (R) (Max - Min) = Average Range (R) = Mean Control Chart Range Control Chart Problem 41 continues on the next page

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