Question: Normal Inverse Distribution Calculation Template Enter data only in yellow-shaded cells Mean, m Standard deviation, s Probability P ( X x ) Calculated x-value #NUM!

| Normal Inverse Distribution Calculation Template | |
| Enter data only in yellow-shaded cells | |
| Mean, m | |
| Standard deviation, s | |
| Probability P(X x) | |
| Calculated x-value | #NUM! |
| Normal Distribution Probability Template | |
| Enter data only in yellow-shaded cells | |
| Mean, m | |
| Standard deviation, s | |
| x-value | |
| Calculated z-value | #DIV/0! |
| F(x) = P(X x) | #NUM! |
6. Frackly Oil is sold in 900 milliliter (ml) cans. The mean volume of oil placed in a can is 880ml with a standard deviation of 7.8ml. Assuming a normal distribution of the data, what is the probability that the filling machine will cause an overflow in a can, that is, the probability that more than 900ml will be placed in the can
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