Note: Make sure to develop some intuition about what the answer will be like, before plugging into the equation.

An object of height $y_0=+2m$ is placed in front of a convex spherical mirror $($focal length of size $3$ m $),$ at the various locations listed in parts a$-$c$.$

a$.)$ When the object is placed $7$ m away from the mirror, please find:

image distance $=$ m

type$/$orientation of image $=$ virtual and upright $$

magnification $=.$

height of image $=$ m

b$.)$ When the object is placed $4\mathrm{.}5$ m away from the mirror, please find:

image distance $=q,$ m

type$/$orientation of image $=$ virtual and upright

magnification $=q,$

height of image $=$ m

c$.)$ When the object is placed $1\mathrm{.}5$ m away from the mirror, please find:

image distance $=$ m

type$/$orientation of image $=$ virtual and upright

magnification $=q,$

height of image : $q,$ m

The same object $($of height $=2m)$ is placed in front of a diverging lens $($focal length of size $3$ m $),$ at the various locations listed in parts d$-$f$.$

d$.)$ When the object is placed $7$ m away from the lens, please find:

image distance $=q,$ m

type$/$orientation of image $=$ virtual and upright

magnification $=$

height of image $=$ m

e$.)$ When the object is placed $4\mathrm{.}5$ m away from the lens, please find:

image distance $=$ m

type$/$orientation of image $=$ virtual and upright darr

magnification $=q,$

height of image $=$ m

f$.)$ When the object is placed $1\mathrm{.}5$ m away from the lens, please find:

image distance $=$ m

type$/$orienfation of image $=$ virtual and upright

magnification $=q,$

height of image $=$ m