Note: NEEDS A LOOP A common year in the modern Gregorian Calendar consists of $365$ days. In reality, Earth takes longer to rotate around the sun. To account for the difference in time, every $4$ years, a leap year takes place. A leap year is when a year has $366$ days: An extra day, February $29$th$.$ The requirements for a given year to be a leap year are: $1)$ The year must be divisible by $42)$ If the year is a century year $(1700,1800,$ etc.$),$ the year must be evenly divisible by $400$; therefore, both $1700$ and $1800$ are not leap years Some example leap years are $1600,1712,$ and $2016.$ Write a program that takes in a year and determines the number of days in February for that year. Ex: If the input is: $1712$ the output is: $1712$ has $29$ days in February. Ex: If the input is: $1913$ the output is: $1913$ has $28$ days in February. $($I cant get $10/10)$