Question: Note: The text is enciphered using exponentiation cipher. If p = 29 and the enciphering k is 11, decipher 23 03 27 10 05 12

 Note: The text is enciphered using exponentiation cipher. If p =

Note: The text is enciphered using exponentiation cipher.

If p = 29 and the enciphering k is 11, decipher 23 03 27 10 05 12

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