Question: Now compute these probabilities: P ( O , x = H H H ) = P ( M | H ) P ( S |

Now compute these probabilities:
P(O,x=HHH)=P(M|H)P(S|H)P(L|H)=0.40.10.1=0.004
P(O,x=HHC)=P(M|H)P(S|H)P(L|C)=0.40.10.5=0.02
P(O,x=HCH)=P(M|H)P(S|C)P(L|H)=0.40.70.1=0.028
P(O,x=HCC)=P(M|H)P(S|C)P(L|C)=0.40.70.5=0.14
P(O,x=CHH)=P(M|C)P(S|H)P(L|H)=0.20.10.1=0.002
P(O,x=CHC)=P(M|C)P(S|H)P(L|C)=0.20.10.5=0.01
P(O,x=CCH)=P(M|C)P(S|C)P(L|H)=0.20.70.1=0.014
P(O,x=CCC)=P(M|C)P(S|C)P(L|C)=0.20.70.5=0.07
Now, summing up these probabilities:
P(O|)=0.004+0.02+0.028+0.14+0.002+0.01+0.014+0.07=0.288
So,P(O|)=0.288.
Now compute i(t) using the provided formulas:
Initialize:
0(0)=0b0(O0)=1.00.4=0.4
0(1)=1b1(O0)=0.00.2=0.0
Recursion:
1(0)=(0(0)a00+0(1)a10)b0(O1)=(0.40.7+0.00.4)0.1=0.028
1(1)=(0(0)a01+0(1)a11)b1(O1)=(0.40.3+0.00.6)0.4=0.048
Recursion:
2(0)=(1(0)a00+1(1)a10)b0(O2)=(0.0280.7+0.0480.4)0.5=0.0194
2(1)=(1(0)a01+1(1)a11)b1(O2)=(0.0280.3+0.0480.6)0.1=0.00372
Finally, we sum over the final values of i(T-1) to getP(O|) :
P(O|)=i=0N-12(i)=2(0)+2(1)=0.0194+0.00372=0.02312
So,P(O|)=0.02312.
For this problem, use the same model and observation sequence O
given in Problem 1.
a) Determine the best hidden state sequence (x0,x1,x2) in the dy-
namic programming sense.
b) Determine the best hidden state sequence (x0,x1,x2) in the HMM
sense.
CAN YOU ANSWER QUESTION 2 PART A AND B. QUESTION 1 ANSWERS ARE PROVIDED
Now compute these probabilities: P ( O , x = H H

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