Question: Now compute two equal - tangent vertical curves, one from B V C to C V C and another from CVC to EVC, by the

Now compute two equal-tangent vertical curves, one from BVC to CVC and another from CVC to EVC, by the methods of Section 25.4. Since both curves are tangent to the same line AB at point CVC, they will be tangent to each other and form a smooth curve.
Example 25.4
For the configuration of Figure 25.6, compute and tabulate the notes necessary to stake the unequal-tangent vertical curve at full stations.
Solution
Calculate elevations of BVC,EVC,A,B, and CVC, and grade AB
()BVC()AB
These elevations are shown in Figure 25.6.
2. In computing the first curve, the grade of AB will be g2 in the formulas, and for the second curve it will be g1. The rates of change of grade for the two curves are, by Equation (25.4)
r1=0.16-(-2.00)4=+0.54%station
r2=1.60-0.166=+0.24%station
Figure 25.6 Unequal-tangent vertical curve.
770 VERTICAL CURVES
TABLE 25.3 NOTES FOR CURVE OF EXAMPLE 25.3
\table[[Station,x(sta),g1x,rx22,\table[[Curve],[Elevation]],\table[[First],[Difference]],\table[[Second],[Difference]]],[93+00(EVC),6,0.96,4.32,752.84,1.48,],[92+00,5,0.80,3.00,751.36,1.24,0.24],[91+00,4,0.64,1.92,750.12,1.00,0.24],[90+00,3,0.48,1.08,749.12,0.76,0.24],[89+00,2,0.32,0.48,748.36,0.52,0.24],[88+00,1,0.16,0.12,747.84,0.28,0.24],[87+00(CVC),4,-8.00,4.32,747.56,-0.11,],[86+00,3,-6.00,2.43,747.67,-0.65,0.54],[85+00,2,-4.00,1.08,748.32,-1.19,0.54],[84+00,1,-2.00,0.27,749.51,-1.73,0.54],[83+00(BVC),0,0.00,0.00,751.24,,]]
Now compute two equal - tangent vertical curves,

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Civil Engineering Questions!