Question: Now factor the trinomial u 2 29 u +100, and then substitute u = x 2 . u 2 29 u +100 = ( u

Now factor the trinomial

u229u+100,

and then substitute

u=x2.

u229u+100 =

(u25)

=

(x225)

To factor the polynomial

P(x) =x525x3+144x,

first factor out the common factor.

x525x3+144x=x

To evaluate

P(2.9)

and

P(3.8),

we will use synthetic division and examine the remainder. We start with evaluating

P(2.9).

Perform the synthetic division with

c=2.9.

2.9 1 0 1 1 7
1

Therefore,

P(2.9) = .

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