Now, find $y^{\text{'}}$ for the implicit function $5x{e}^{-2y}-x^3=14$

Differentiating both sides of the equation by x gives $?$

Your answer in the line above should be in terms of $x,y,$ and $\frac{dy}{dx}.$ Note, $y^{\text{'}}=\frac{dy}{dx}.$ To enter $\frac{dy}{dx},$ type diff$((y,x)$ So$,$ solving the equation $=0$ for $\frac{dy}{dx},$ gives us $\frac{dy}{dx}=$ Your answer in the line above should be in terms of $x$ and $y$

So$,y^{\text{'}}=$