Obtain the general solution $to$ the equation.

$(x^2+16)\frac{dy}{dx}+xy=3x,y(0)=1$

The general solution $isy=3+\frac{C}{\sqrt[\phantom{2}]{x^2+16}}.$

The particular solution for $y(0)=1isy=3-\frac{8}{\sqrt[\phantom{2}]{x^2+16}}.$