OK$,$ I am going to help you to start. As stated before, the first field that is inserted in the cover file is a $4-$byte integer

that represents the number of characters of the secret message. So$,$ let us get the first $32$ bits from the bitmap data

part, as depicted in Table $4.$

Table $4$: Getting the Size of the Secret Message

The binary value is $(000001010000000000000000000000{)}_2,$ which is $(05000000{)}_{16}$ in hexadecimal. Since

integers are stored in the Little$-$Endian format, the size is $(00000005{)}_{16}$ or $5$ in decimal. That is$,$ the secret message

has five characters. What is the number of bytes in the bitmap data? Give a justification for this number. What is the

hidden message?