Okay, so we had solid benzoic acid, ethyl 4- aminobenzoate, and 9-fluorenone all dissolved in diethyl ether (4ml). We separated the basic component by adding 3M HCl, we separated the acidic component by adding 3M NaOH. I don't understand what happens here. To isolate the acidic solution, we added 6 M NaOH and used the vacuum to recover the solid. To isolate the basic solution we added 6M HCl. Here are the questions I am having trouble with...

1. Why are each of the three solids (the carboxylic acid, the amine and the ketone) soluble in diethyl ether? Examine the structures of each solute and explain what factors increase solubility in water versus the organic solvent used. Identify the significant INTERMOLECULAR FORCES affecting solubility

2. Explain why two layers formed when 3M HCl was added to the ether solution of the ketone, acid and base. What solvents do the two layers represent? Which solvent forms the upper layer? Why?

3. Draw an equation to illustrate the chemical reaction that occurs when HCl was added to the ether solution.

4. What chemical(s) dissolved in to the upper layer? What chemical(s) went in to the lower layer? Why?

Answer rating: 100% (QA)

Solubility of substance is based on the principle Like to Like This means polar solutes dissolve in ... View the full answer