Once a rocket enters into space, it drops its staged boosters and relies on only the capsule to travel. Suppose that the space capsule with two empty boosters has mass of 500 kg and initial velocity vo = 290 i when explosive charges detach the boosters from the craft. After 4 seconds, it is known that the position of the 250 kg booster A is A(365,329,-972) and the position of the 200 kg booster B is B(280,472,-758). Assume that gravity is negligible (it's officially called microgravity) and calculate the position of the 50 kg capsule. The position of the capsule is 3+ k. Question Help: Written Example Submit