only part d

6 3. (20 points) A closed-loop conveyor system is to be installed to deliver parts needed for the assembly tasks shown below. The Largest Candidate Rule method is used to balance the assembly line. Element 1 2 3 4 5 6 Time 0.25 0.70 0.40 0.50 0.65 0.20 It is known that 50 feet of the floor space along the conveyor is available for installing assembly stations. Each workstation should have 6 feet space and the clearance between two adjacent stations is 4 feet. There is one input device and one output device to feed the conveyor and collect the finished product. The time for loading or unloading a part - 0.5 min. If the production rate = 80 units/hour, determine: (a) the conveyor speed Loading Unloading = 0.5 min In und there taken - 10min (b) maximum number of workstations that can be allocated along the conveyor. Wola 60 16 work staten maximum 6th Tek Kuku (c) Number of station and tasks assigned to cach station based on the LCR method. 6w.s= 6x6 = 36 feet Station Task Cumulative Time (0.25 +0.50 +0.63) = + 1 2 125 170 - 25 .95 (0.25)+ ( 70 ) + 120 4.65=( 20 ( 1.80 6 (25) +140) t . lun 1.661 => (d) Maximum number of units that can be produced per day (in 400 minutes). 1, 2, t, 64