Question: Only Problems 27-30 f(x) = 2 /65 f' (x) = 10x- 10 ds -5 dt slope of the tangent at x = -1 is f'(-1)

Only Problems 27-30

Only Problems 27-30 f(x) = 2 /65 f' (x) =
f(x) = 2 /65 f' (x) = 10x- 10 ds -5 dt slope of the tangent at x = -1 is f'(-1) = 11. 23. f(x) = 5x-4/5 + 2x-4/3 ms 1-14. 24. f(x) = 6x-8/3 - x-2/3 3 25. g(x) = - + 2x - 7x x 7 4 -9 26. h(x) = 7 3 + 8Vx In Problems 27-30, write the equation of the tangent line to each curve at the indicated point. As a check, graph both the function and the tangent line. 27. y = x - 5x+7 atx =1 28. y = x* - 4x3 - 2 atx = 2 29. f(x ) = 4x2 at x = X 2 ion. 3 30. f (x) = at x = -1 3 In Problems 31-34, find the coordinates of points where the graph of f(x) has horizontal tangents. As a check, tion. graph f(x) and see whether the points you found look as though they have horizontal tangents. 31. f(x) =-x+9x2 - 15x + 6 3 32. f(x) = =x -3x - 16x +8

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