Question: Only solve for registration no 25 data. Complex Engineering Problem Consider a system for which you have been given the ternary diagram. Acetone ( A=

Only solve for registration no 25 data.

$A= solute), MIK(S= solvent (100\% pure)), Water (C= carrier). The feed flow-rate$

Complex Engineering Problem Consider a system for which you have been given the ternary diagram. Acetone ( A= solute), MIK(S= solvent (100\% pure)), Water (C= carrier). The feed flow-rate and composition can be seen against your registration number in the Appendix below. 1. Calculate the flow and composition of the extract and raffinate from: - 1st cross-current stage, using a pure solvent flow of 70kg/hr. - 2nd cross-current stage, with an additional solvent flow of 30kg/hr. 2. For the overall 2-stage cross-current system, find the: - overall recovery - overall concentration of combined extract streams The objective now is to have a counter-current system so the raffinate leaving in the Nth stage, RN has yR=0.015 3. Show the construction on the ternary diagram for the number of equilibrium stages to achieve yRN =0.015, given a solvent flow of 28kg/hr. 4. Calculate the overall recovery and concentration of the extract stream. s. Plot on the same axes the concentrations in the extract and raffinate streams. 6. Repeat the procedure using two counter current flow stages and find the overall recovery and concentration of the extract. Compare and discuss the results. Based on results, propose which operation (cross flow or counter flow) is suitable for the recovery of Acetone. MIK + acetone + water at 298.15K Complex Engineering Problem Consider a system for which you have been given the ternary diagram. Acetone ( A= solute), MIK(S= solvent (100\% pure)), Water (C= carrier). The feed flow-rate and composition can be seen against your registration number in the Appendix below. 1. Calculate the flow and composition of the extract and raffinate from: - 1st cross-current stage, using a pure solvent flow of 70kg/hr. - 2nd cross-current stage, with an additional solvent flow of 30kg/hr. 2. For the overall 2-stage cross-current system, find the: - overall recovery - overall concentration of combined extract streams The objective now is to have a counter-current system so the raffinate leaving in the Nth stage, RN has yR=0.015 3. Show the construction on the ternary diagram for the number of equilibrium stages to achieve yRN =0.015, given a solvent flow of 28kg/hr. 4. Calculate the overall recovery and concentration of the extract stream. s. Plot on the same axes the concentrations in the extract and raffinate streams. 6. Repeat the procedure using two counter current flow stages and find the overall recovery and concentration of the extract. Compare and discuss the results. Based on results, propose which operation (cross flow or counter flow) is suitable for the recovery of Acetone. MIK + acetone + water at 298.15K

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