Question: onsider the following.f(x)=exif x <1x3if x 1, a =1(a)Find the left-hand and right-hand limits at the given value of a.limx1f(x)=limx1+f(x)=(b)Explain why the function is discontinuous

onsider the following.f(x)=exif x <1x3if x 1, a =1(a)Find the left-hand and right-hand limits at the given value of a.limx1f(x)=limx1+f(x)=(b)Explain why the function is discontinuous at the given number a.Since these limits are ---Select--- equal not equal ,limx1f(x)---Select--- exists does not exist and f is therefore discontinuous at 1.

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