-p 2. **pk, char **pv) (10pt) /StringImplement void which takes a string s in the form of "key:value" and dynamically creates two new strings "key" and "value" whose references will be returned through pk and pv. If the string s does not contain' or memory allocations fail, make sure you return NULL through splits tr (char *s, char ; pk and pv For example, after char k, v split_str ("abcd:klm", &k, &v) Vi k points to "abcd" and v points to "klm" After char *k, split_str ("myKeymyValue", &k, &v); is NULL and vs NULL /* give your solution to this problem in the next page