Question: ( P & Q ) notR; ( Q & R ) notP,not ( P v Q ) not ( Q v R ) | -

(P&Q)notR;(Q&R)notP,not(PvQ)not(QvR)|--not(P&(notQ&R))|
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 (P&Q)notR;(Q&R)notP,not(PvQ)not(QvR)|--not(P&(notQ&R))| Create a tree

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