P4 is prepared by heating phosphate rock [principally Ca3(PO4)2] with sand and coke: Ca3(PO4)2(s) + SiO2(s) +
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P4 is prepared by heating phosphate rock [principally Ca3(PO4)2] with sand and coke:
Ca3(PO4)2(s) + SiO2(s) + C(s) -> CaSiO3(s) + CO(g) + P4(g) [unbalanced]
How many kilograms of phosphate rock are needed to produce 315 mol of P4, assuming that the conversion is 90.% efficient?
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