Question: Part 2: Type inference Below are several type definitions. You do not need to know the implementations of the functions or the undefined Glob' type


Part 2: Type inference Below are several type definitions. You do not need to know the implementations of the functions or the undefined Glob' type in order to solve the problems. data Result a = OK a Error String show :: Glob -> String build :: Int -> Glob (.) :: (b-> c) -> (a -> b)-> a -> C Part 2.1: Determine the type of a sub-expression For each of the following problems, determine what the type of the unknown value must be in order for the overall expression to have the given type. For example, given the following facts: build foo :: Glob bar True :: Int -> Int Then it must be the case that 'foo' and 'bar' have the following types: foo :: Int bar :: Bool -> Int -> Int (Brief explanation: 'foo' must be an 'Int' since it's passed as an argument to 'build', and 'bar' is a function that returns a function from 'Int -> Int' when given one 'Bool'.) 1. Given the following fact, what is the type of 'foo'? OK (show foo) :: Result String foo :: 2. Given the following fact what is the type of 'bazi? 2. Given the following fact, what is the type of 'baz'? show . bar :: String -> String bar :: Part 2.2: Construct a value of the given type For each of the following problems, create an expression of the indicated type using only the types and functions defined above. 1. Result (Int -> Glob) 2. Glob -> Result a Part 2: Type inference Below are several type definitions. You do not need to know the implementations of the functions or the undefined Glob' type in order to solve the problems. data Result a = OK a Error String show :: Glob -> String build :: Int -> Glob (.) :: (b-> c) -> (a -> b)-> a -> C Part 2.1: Determine the type of a sub-expression For each of the following problems, determine what the type of the unknown value must be in order for the overall expression to have the given type. For example, given the following facts: build foo :: Glob bar True :: Int -> Int Then it must be the case that 'foo' and 'bar' have the following types: foo :: Int bar :: Bool -> Int -> Int (Brief explanation: 'foo' must be an 'Int' since it's passed as an argument to 'build', and 'bar' is a function that returns a function from 'Int -> Int' when given one 'Bool'.) 1. Given the following fact, what is the type of 'foo'? OK (show foo) :: Result String foo :: 2. Given the following fact what is the type of 'bazi? 2. Given the following fact, what is the type of 'baz'? show . bar :: String -> String bar :: Part 2.2: Construct a value of the given type For each of the following problems, create an expression of the indicated type using only the types and functions defined above. 1. Result (Int -> Glob) 2. Glob -> Result a
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