Part #$4$ Final Power Factor Correction

Determine the amount of apparent power that would produce the desired power factor to correct this new value to $0\mathrm{.}95.$ A WYE connected capacitor bank will be installed.

$V{A}_{\text{d}\text{e}\text{s}\text{i}\text{r}\text{e}\text{d}}=\frac{P_{present}}{P{F}_{\text{d}\text{e}\text{s}\text{i}\text{r}\text{e}\text{d}}}$

Determine the amount of reactive power that would produce the desired amount of apparent power.

$VAR{s}_{\text{d}\text{e}\text{s}\text{i}\text{r}\text{e}\text{d}}=\sqrt[\phantom{2}]{((V{A}_{\text{d}\text{e}\text{s}\text{i}\text{r}\text{e}\text{d}}{)}^2-(P_{present}{)}^2)}$

Determine the capacitive VARs necessary to produce the desired reactive power. $VAR{s}_{C\text{n}\text{e}\text{e}\text{d}\text{e}\text{d}}=VAR{s}_{present}-VAR{s}_{\text{d}\text{e}\text{s}\text{i}\text{r}\text{e}\text{d}}$

Determine the amount of capacitive current necessary to produce the capacitive VARs needed.

$I_C=\frac{VAR{s}_{C\text{n}\text{e}\text{e}\text{d}\text{e}\text{d}}}{E_L\sqrt[\phantom{2}]{3}}$