Question: Part A A 6 0 . 0 k g grindstone is a solid disk 0 . 5 2 0 m in diameter. You press an

Part A
A 60.0kg grindstone is a solid disk 0.520m in diameter.
You press an ax down on the rim with a normal force of
F=180N(Figure 1). The coefficient of kinetic friction
between the blade and the stone is 0.60, and there is a
constant friction torque of 6.50N*m between the axle of
the stone and its bearings.
Figure
How much force must be applied tangentially at the end of a crank handle
0.500m long to bring the stone from rest to 120revmin in 7.00s?
Express your answer with the appropriate units.
F1=,||
Previous Answers Request Answer
Incorrect; Try Again; 4 attempts remaining
Part B
After the grindstone attains an angular speed of 120revmin, what tangential
force at the end of the handle is needed to maintain a constant angular speed of
120revmin?
Express your answer with the appropriate units.
F2=
Request Answer
Part C
How much time does it take the grindstone to come from 120revmin to rest if it
is acted on by the axle friction alone?
Express your answer with the appropriate units.
t=
t=
[
 Part A A 60.0kg grindstone is a solid disk 0.520m in

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Physics Questions!