Question: Part A In ( Figure 1 ) , R = 1 3 . 0 and the battery emf is 6 . 3 0 V .

Part A
In (Figure 1),R=13.0 and the battery emf is 6.30V.
With switch S2 open, switch S1 is closed. After several
minutes, S1 is opened and S2 is closed.
At 2.20ms after S1 is opened, the current has decayed to 0.240A. Calculate the inductance of the coil.
Express your answer with the appropriate units.
L=
Request Answer
Part B
How long after S1 is opened will the current reach 1.00% of its original value?
Express your answer with the appropriate units.
t=[,]
 Part A In (Figure 1),R=13.0 and the battery emf is 6.30V.

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Physics Questions!