In $($Figure $1),$ suppose that $E=56\mathrm{.}0V,R=250\mathrm{.}0$ and $L=0\mathrm{.}170H.$ With switch $S_2$ open, switch $S_1$ is left closed until a constant current is established. Then $S_2$ is closed and $S_1$ opened, taking the battery out of the circuit.

What is the initial current in the resistor, just after $S_2$ is closed and $S_1$ is opened? Express your answer in amperes.

In $($Figure $1),$ suppose that $E=56\mathrm{.}0V,R=250\mathrm{.}0$ and $L=0\mathrm{.}170H$ With switch $S_2$ open, switch $S_1$ is left closed until a constant current is established. Then $S_2$ is closed and $S_1$ opened, taking the battery out of the circuit.

Figure

$1$ of $1$

$I=$

A

Request Answer

Part B

What is the current in the resistor at $t=4\mathrm{.}20{10}^{-4}s?$

Express your answer in amperes.

Request Answer

Part C

What is the potential difference between points $b$ and $c$ at $t=4\mathrm{.}20{10}^{-4}s?$

Express your answer in volts.

$V=$

V