Part A

Select the correct equations that show that the output voltage is $19$ V $.$

$V_{\text{o}\text{u}\text{t}}=V_{in}*\frac{N_{\text{p}\text{r}\text{i}\text{m}\text{a}\text{r}\text{y}}}{N_{secondary}}=(190V)*\frac{100\text{t}\text{u}\text{r}\text{n}\text{s}}{10\text{t}\text{u}\text{r}\text{n}\text{s}}=19V$

$V_{\text{o}\text{u}\text{t}}=\frac{V_{in}}{N_{\text{p}\text{r}\text{i}\text{m}\text{a}\text{r}\text{y}}*N_{secondary}}=\frac{190(V)}{(100\text{t}\text{u}\text{r}\text{n}\text{s})(10\text{t}\text{u}\text{r}\text{n}\text{s})}=19V$

$V_{\text{o}\text{u}\text{t}}=V_{in}*\frac{N_{secondary}}{N_{\text{p}\text{r}\text{i}\text{m}\text{a}\text{r}\text{y}}}=(190V)*\frac{10\text{t}\text{u}\text{r}\text{n}\text{s}}{100\text{t}\text{u}\text{r}\text{n}\text{s}}=19V$

$V_{\text{o}\text{u}\text{t}}=\frac{N_{\text{p}\text{r}\text{i}\text{m}\text{a}\text{r}\text{y}}}{V_{in}*N_{secondary}}=\frac{100\text{t}\text{u}\text{r}\text{n}\text{s}}{(190(V))(10\text{t}\text{u}\text{r}\text{n}\text{s})}=19V$