Part D

Select the correct expression that gives the block's acceleration at a displacement $x$ from the equilibrium position. Note that $x$ can be either positive or negative; that is$,$ the block can be either to the right or left of its equilibrium position.

View Available Hint$($s$)$

$a=-kx$

$a=kx$

$a=\frac{k}{m}x$

$a=-\frac{k}{m}x$