Part Description Answer Save Status A The calculation to find work from a to b is (600kPa 120kPa)( 5m 3 2m 3 ) (600kPa 120kPa)( 5m 3 2m 3 ) (600kPa)( 5m 3 2m 3 ) (600kPa)( 5m 3 2m 3 ) (120kPa)( 5m 3 2m 3 ) (120kPa)( 5m 3 2m 3 ) No calculation required W 0 8 33 pts 100 14 try penalty tries 0 B Using the figure from part A, the calculation to find work from b to c is (600kPa 120kPa)( 5m 3 2m 3 ) (600kPa 120kPa)( 5m 3 2m 3 ) (600kPa)( 5m 3 2m 3 ) (600kPa)( 5m 3 2m 3 ) (120kPa)( 5m 3 2m 3 ) (120kPa)( 5m 3 2m 3 ) No calculation required W 0 8 33 pts 100 14 try penalty tries 0 C Using the figure from part A, the calculation to find work from c to d is (600kPa 120kPa)( 5m 3 2m 3 ) (600kPa 120kPa)( 5m 3 2m 3 ) (600kPa)( 5m 3 2m 3 ) (600kPa)( 5m 3 2m 3 ) (120kPa)( 5m 3 2m 3 ) (120kPa)( 5m 3 2m 3 ) No calculation required W 0 8 33 pts 100 14 try penalty tries 0 D Using the figure from part A, the calculation to find work from d to a is (600kPa 120kPa)( 5m 3 2m 3 ) (600kPa 120kPa)( 5m 3 2m 3 ) (600kPa)( 5m 3 2m 3 ) (600kPa)( 5m 3 2m 3 ) (120kPa)( 5m 3 2m 3 ) (120kPa)( 5m 3 2m 3 ) No calculation required W 0 8 33 pts 100 14 try penalty tries 0 E Using the figure from part A, how would you calculate the net work Force distance area enclosed add up all the work from each process both 1 2 both 2 3 both 1 3

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Question: Part Description Answer Save Status A. The calculation to find work from a to b is: (600kPa-120kPa)(.5m 3 -.2m 3 ) -(600kPa-120kPa)(.5m 3 -.2m 3

Part	Description	Answer	Save	Status
A.	The calculation to find work from a to b is: (600kPa-120kPa)(.5m³-.2m³) -(600kPa-120kPa)(.5m³-.2m³) (600kPa)(.5m³-.2m³) -(600kPa)(.5m³-.2m³) (120kPa)(.5m³-.2m³) -(120kPa)(.5m³-.2m³) No calculation required. W = 0		8.33 pts.^100% 14% try penalty	# tries: 0
B.	Using the figure from part A, the calculation to find work from b to c is: (600kPa-120kPa)(.5m³-.2m³) -(600kPa-120kPa)(.5m³-.2m³) (600kPa)(.5m³-.2m³) -(600kPa)(.5m³-.2m³) (120kPa)(.5m³-.2m³) -(120kPa)(.5m³-.2m³) No calculation required! W = 0		8.33 pts.^100% 14% try penalty	# tries: 0
C.	Using the figure from part A, the calculation to find work from c to d is: (600kPa-120kPa)(.5m³-.2m³) -(600kPa-120kPa)(.5m³-.2m³) (600kPa)(.5m³-.2m³) -(600kPa)(.5m³-.2m³) (120kPa)(.5m³-.2m³) -(120kPa)(.5m³-.2m³) No calculation required. W = 0		8.33 pts.^100% 14% try penalty	# tries: 0
D.	Using the figure from part A, the calculation to find work from d to a is: (600kPa-120kPa)(.5m³-.2m³) -(600kPa-120kPa)(.5m³-.2m³) (600kPa)(.5m³-.2m³) -(600kPa)(.5m³-.2m³) (120kPa)(.5m³-.2m³) -(120kPa)(.5m³-.2m³) No calculation required! W = 0		8.33 pts.^100% 14% try penalty	# tries: 0
E.	Using the figure from part A, how would you calculate the net work? Force*distance area enclosed add up all the work from each process both 1 & 2 both 2 & 3 both 1 & 3

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