Question: Passing a C string to a function copies a pointer to the address of the string, not the string itself
Passing a C string to a function copies a pointer to the address of the string, not the string itself
Step by Step Solution
There are 3 Steps involved in it
1 Expert Approved Answer
Step: 1 Unlock
Question Has Been Solved by an Expert!
Get step-by-step solutions from verified subject matter experts
Step: 2 Unlock
Step: 3 Unlock
