Question: Place two charged insulating plates parallel to each other. The charge densities on the left and right insulating plates are sigma 1 = + 1

Place two charged insulating plates parallel to each other. The charge densities on the left and right insulating plates are sigma 1=+1.0sigma and sigma 2=1.0sigma , where sigma =1.6 nC/m2. The vacuum permittivity is 0=8.85421012 C2/(Nm2).

a) Calculate the electric field in region B. The positive direction is from left to right.

EB=

The plates are separated by a distance d=2.5 cm. A positively charged particle (charge q=1.1mu C), with a mass m=0.13 g, starts moving from rest at time t=0 from the positively charged plate between the plates.

b) What is the particle's acceleration between the plates?

a=

c) At what time does the particle collide with the negatively charged plate?

t=

d) What is the particle's collision velocity?

v=

d + I C | I  + + + + + A 02 01

d + I C | I + + + + + A 02 01

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a The electric field E between two charged parallel plates with charge densities 1 and 2 can be calculated using the formula E 1 2 2 0 Where 0 is the ... View full answer

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