Question: Two parallel plates having charges of equal magnitude but opposite sign are separated by 12.0 cm. Each plate has a surface charge density of 36.0
(a) The potential difference between the plates,
(b) The kinetic energy of the proton when it reaches the negative plate,
(c) The speed of the proton just before it strikes the negative plate,
(d) The acceleration of the proton, and
(e) The force on the proton.
(f) From the force, find the magnitude of the electric field and show that it is equal to the electric field found from the charge densities on the plates.
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b The positive plate by itself creates a field E 203 kNC away f... View full answer
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