Question: Two parallel plates having charges of equal magnitude but opposite sign are separated by 12.0 cm. Each plate has a surface charge density of 36.0

Two parallel plates having charges of equal magnitude but opposite sign are separated by 12.0 cm. Each plate has a surface charge density of 36.0 nC/m2. A proton is released from rest at the positive plate. Determine
(a) The potential difference between the plates,
(b) The kinetic energy of the proton when it reaches the negative plate,
(c) The speed of the proton just before it strikes the negative plate,
(d) The acceleration of the proton, and
(e) The force on the proton.
(f) From the force, find the magnitude of the electric field and show that it is equal to the electric field found from the charge densities on the plates.

Step by Step Solution

3.40 Rating (150 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

b The positive plate by itself creates a field E 203 kNC away f... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

P-M-E-P (60).docx

120 KBs Word File

Students Have Also Explored These Related Electricity and Magnetism Questions!