please answer all on the first picture but using the table on the second picture

Fefer to Table. S6.1 - Factors for Comouting. Control Chart Limits i3 sigma) for this problem. Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as foliows: a) What is the value of x ? x==mm (round your respanse to two decimal places) b) What is the value of A ? c) What are the UCL; and LCLx using 3-sigma? Upper Control Limit (UCL-) = mm (round your response to two decimal places). Lower Control Limit (LCL)=men (round your response to hwo decimal places). d) What are the CLA and LCLA using 3-sigma? Upper Control Limit (UCL CA) = mm (round your response to two decimal places). Lower Control Limit (LCLA)=mm (round your response to mo decimal places). e) If the true diameter mean should be 155 mm and you want this as your center (nominal) line, what are the new UCL. and LCL-? Upper Control Limit (UCL- = ) = mm (round your response to two decimal places) Lower Control Limit (LCL ) = mm (round your response to nwo decimal piaces). Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: T) What is the value of x