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12. (4 points) What is the most likely product when this epoxide is treated with CH3MgBr2 ? a. I because this reaction is more SN l-like and not in acid (in first step), since the first step is nucleophilic attack on the more hindered carbon. b. I because this reaction is more SN2-like and not in acid (in first step), since the first step is nucleophilic attack on the least hindered carbon. c. II because this reaction is more SN-like and not in acid (in first step), since the first step is nucleophilic attack on the least hindered carbon. d. II because this reaction is more SN l-like and not in acid (in first step), since the first step is nucleophilic attack on the more hindered carbon