Question: In a AABC, the median AD divides ZBACsuch that ZBAD : LCAD :: 2:1 then () is equal to cos (A) 2 sin B

In a AABC, the median AD divides ZBACsuch that ZBAD : LCAD

In a AABC, the median AD divides ZBACsuch that ZBAD : LCAD :: 2:1 then () is equal to cos (A) 2 sin B sin C (B) sin C 2 sin B sin B (C) 2 sin C sin B (D) 3 sin C

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