Question: PLEASE ANSWER PART 3 WITH MATLAB P514B The dehydration of butanol is carried out over a silicaalumina catalyst at 680K. CH3CH2CH2CH2OHcatCH3CH=CHCH3+H2O The rate law is

PLEASE ANSWER PART 3 WITH MATLAB

PLEASE ANSWER PART 3 WITH MATLAB P514B The dehydration of butanol is

P514B The dehydration of butanol is carried out over a silicaalumina catalyst at 680K. CH3CH2CH2CH2OHcatCH3CH=CHCH3+H2O The rate law is rBu=(1+KBuPBu)2kPBu with k=0.054mol/ gcat hatm and KBu=0.32atm1. Pure butanol enters a thin-tubed, packed-bed reactor at a molar flow rate of 50kmol/hr and a pressure of 10atm (1013kPa). 1. What PBR catalyst weight is necessary to achieve 80% conversion in the absence of pressure drop? Plot and analyze X,p,f( i.e., (v/v0)) and reaction rate, rA, as a function of catalyst weight. 2. What "fluidized CSTR" catalyst weight is necessary to achieve 80% conversion? 3. Repeat (a) when there is pressure drop, with the pressure-drop parameter =0.0006kg1. Do you observe a maximum in the rate of reaction, and if so, why? What catalyst weight is necessary to achieve 70% conversion? Compare this weight with that for no pressure drop to achieve the same conversion

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