Please answer the ones I got wrong

Consider the transportation table below. The solution displayed was obtained by performing some iterations of the transportation method on this problem. Source 1 Destination 2 $30 3 Capacity $30 $5 A 35 25 10 $10 $10 $10 B 20 20 $20 $100 $25 70 40 30 40 Demand 25 60 The total cost of the current solution provided = 2150 dollars. Using stepping stone method, to perform an improvement iteration, the improvement index for the unused cell will be: A-2 = 40 B-1 = -40 B-3 - 15 C-1 - - 30 Based on the improvement index for each of the unused cells, in the first improvement iteration, unused cell B-1 should get an assignment of 20 units. a) The improved transportation flow will be: (Note: You must enter a shipment in every cell, even if the shipment is 0.) From 1 Capacity $30 $30 $ $5 35 2 3 A $100 $10 $101 IB 20 $20 $10 $25 C 70 b) The total cost of the improved solution = 1350 dollars. The solution achieved based on the one improvement, can be further improved by assigning quantity to C-1'. The total cost of the optimal solution = 1175 dollars. Consider the transportation table below. The solution displayed was obtained by performing some iterations of the transportation method on this problem. Source 1 Destination 2 $30 3 Capacity $30 $5 A 35 25 10 $10 $10 $10 B 20 20 $20 $100 $25 70 40 30 40 Demand 25 60 The total cost of the current solution provided = 2150 dollars. Using stepping stone method, to perform an improvement iteration, the improvement index for the unused cell will be: A-2 = 40 B-1 = -40 B-3 - 15 C-1 - - 30 Based on the improvement index for each of the unused cells, in the first improvement iteration, unused cell B-1 should get an assignment of 20 units. a) The improved transportation flow will be: (Note: You must enter a shipment in every cell, even if the shipment is 0.) From 1 Capacity $30 $30 $ $5 35 2 3 A $100 $10 $101 IB 20 $20 $10 $25 C 70 b) The total cost of the improved solution = 1350 dollars. The solution achieved based on the one improvement, can be further improved by assigning quantity to C-1'. The total cost of the optimal solution = 1175 dollars