Question: please answer the question below In the figure a thin glass rod forms a semicircle of radius r = 2.01 cm. Charge is uniformly distributed
please answer the question below

In the figure a thin glass rod forms a semicircle of radius r = 2.01 cm. Charge is uniformly distributed along the rod, with +q = 5.21 pC in the upper half and -q= -5.21 pC in the lower half. What is the magnitude of the electric field at P, the center of the semicircle? +9 Number 8.47 Units N/C or V/m
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
