Question: please assist with this practice problem a) You have a 40 - 60 mixture of n-hexane and n-octane that you want to separate using simple

please assist with this practice problem
a) You have a 40 - 60 mixture of n-hexane and n-octane that you want to separate using simple batch distillation at 101 kPa total pressure. You condense and collect the vapor fraction after 10% of the original liquid is distilled. What is the average composition of the vapor and remaining liquid after 10% is distilled? Assume that the mixture is ideal, that is, the activity coefficient is 1 for all liquid compositions.
For N-Hexane (1): lnvap/ = 13.8193 2696.04/(T+209.635) , boiling point is 68.7 C
For N-Octane (2): lnvap/ = 13.9346 3123.13/(T+209.635) , boiling point is 125.6 C
b) You continue distilling another 10% of the original liquid and you condense and collect this second fraction in a separate container from the first fraction. What is the average vapor composition of this second batch?

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Chemical Engineering Questions!