Question: please can you help me answer the questions attached thank you A population has standard deviation o = 17.5. Part 1 of 2 (a) How
please can you help me answer the questions attached thank you











A population has standard deviation o = 17.5. Part 1 of 2 (a) How large a sample must be drawn so that a 99.5% confidence interval for u will have a margin of error equal to 3.97 Round the critical value to no less than three decimal places. Round the sample size up to the nearest integer. A sample size of is needed to be drawn in order to obtain a 99.5% confidence interval with a margin of error equal to 3.9. Part 2 of 2 (b) If the required confidence level were 90%, would the necessary sample size be larger or smaller? (Choose one) , because the confidence level is (Choose one) Larger X 5 SmallerA population has standard deviation o = 17.5. Part 1 of 2 (a) How large a sample must be drawn so that a 99.5% confidence interval for u will have a margin of error equal to 3.9? Round the critical value to no less than three decimal places. Round the sample size up to the nearest integer. A sample size of is needed to be drawn in order to obtain a 99.5% confidence interval with a margin of error equal to 3.9. Part 2 of 2 (b) If the required confidence level were 90%, would the necessary sample size be larger or smaller? (Choose one) v , because the confidence level is (Choose one) higher X 5 lowerFor the given confidence level and values of X and n, find the following. x =47, n=96, confidence level 80% Part 1 of 3 LT (a) Find the point estimate. Round the answers to at least four decimal places, if necessary. The point estimate for the given data is 0.4896 Part 2 of 3 (b) Find the standard error. Round the answers to at least four decimal places, if necessary. The standard error for the given data is |0,05102 Part: 2 / 3The point estimate for the given data is U.4030 Part 2 of 3 (b) Find the standard error. Round the answers to at least four decimal places, if necessary. The standard error for the given data is | 0.05102 Part: 2 / 3 Part 3 of 3 (c) Find the margin of error. Round the answers to at least four decimal places, if necessary. The margin of error for the given data isSmart phone: Among 242 cell phone owners aged 18-24 surveyed, 107 said their phone was an Android phone. E Perform the following. Part 1 of 3 (a) Find a point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places. The point estimate for the proportion of cell phone owners aged 18 - 24 who have an Android phone is | 0.442 ola Part 2 of 3 (b) Construct a 95% confidence interval for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places. A 95% confidence interval for the proportion of cell phone owners aged 18-24 who have an Android phone is 0.3794
contedoes ence Interval. X 5 does not(b) Construct a 95% confidence interval for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places. A 95% confidence interval for the proportion of cell phone owners aged 18-24 who have an Android phone is 0.3794
conte does not ence Interval. X 5 does(b) Construct a 98% confidence interval for the proportion of people who performed volunteer work during the past year. Round the answer to at least three decimal places. A 98% confidence interval for the proportion of people who performed volunteer work during the past year is 0.3758
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