Question: Please choose the appropriate(s) equation(s) to solve the problem Calls to a tech support center arrive to a Poison process with a rate of 10

Please choose the appropriate(s) equation(s) to solve the problem

Please choose the appropriate(s) equation(s) to

Please choose the appropriate(s) equation(s) to

Please choose the appropriate(s) equation(s) to

Please choose the appropriate(s) equation(s) to

Please choose the appropriate(s) equation(s) toPlease choose the appropriate(s) equation(s) to

Please choose the appropriate(s) equation(s) to

Please choose the appropriate(s) equation(s) to

Please choose the appropriate(s) equation(s) to

Calls to a tech support center arrive to a Poison process with a rate of 10 per hour. The time for a support person to serve one customer is exponentially distributed with a mean of 10 minutes. The support center has 2 technical staff to assist callers. Compute the total time in the system.

a. W = 0.54 hrs

b. W = 5.41 hrs

c. W = 2.74 hrs

d. W = 1.54 hrs

1 = average number of arrivals entering the system per unit of time. L = average number of customers present in the queuing system Lq = average number of customers waiting in line. Ls = average number of customers in service. = W = average time a customer spends in the system. Wq = average time a customer spends in the line. Ws = average time a customer spends in service. Mj = probability of j customers in the system. - M/M/1/GD//o Queuing System p = N/su s =1 = 1- L=p/(1-P) W = L/X = p / (^(1 - 0)) = 1/(u -) A2) Lq = A2 1 (u(A)) W = L/\ = N(U(u )) 0 = . = = . = . = Ls = p 1/ . Ws = 1/ u Equations m/m/1/GD/c/ If Eu, 10 = (1-P)/(1-pc+1) n = pin. (j = 1,2, ..., c) L = p[1 (c+1) pc + c pc+1] / ((1- pc+1) 1 - )) = + - If I = u, m;= 1/(c+1) (j = 0,1,2...,c) L = c/2 = = m/m/1/GD/c/ For all values of land u, = Ls = - 1- Lq = L-LS W = L1 (1(1-1) Wq = Lq/((1-1)) Ws = 1/ u . . Equations m/m/s/gd// Inter arrival and service times are exponential. Assume a single line with multiple with several servers. Whenever j customers are present, min (j, s) server will be occupied, thus Mj = min (j, s)*u. 1; = 1 (j = 0,1,...) Hj = ju (j =0,1, ... s) Mj = su (J = 5+1, s+2,...) = = = m/m/s/gd/olo ; = ((sp)'Tto)/j! = (j=1,...,s) 0} = ((sp)'To)/(s!Si-s) N (j=s, s+1,..) P(js) = ((sp)STT.)/(s!(1-2)) Lq = P(js)p/ (1-0) Wq = P(js)/ (su-x) Ls = Nu Ws = 1/4 TTo = P(js) (s!(1-0))/(sp)s = = m/m/s/gd/|o L = Lq + Nu W = LI 1.- P(js)s!(1-p(sp) Mo + 0.5 T1 p = Nsu 0 = = Table P(j=s) m/m/s/gd/o/o p .10 .20 .30 .40 .50 .55 .60 .65 .70 .75 .80 .85 .90 .95 s=2 .02 .07 .14 .23 .33 .39 .45 .51 .57 .64 .71 .78 .85 .92 s=3 .00 .02 .07 .14 .24 .29 .35 .42 .51 .57 .65 .73 .83 .91 s=4 .00 .00 .04 .09 .17 .23 .29 .35 .43 .51 .60 .69 .79 .89 s=5 .00 .00 .02 .06 .13 .18 .24 .30 .38 43 .55 .65 .76 .88 s=6 .00 .00 .01 .04 .10 .14 .20 .26 .34 .38 .52 .62 .74 s=7 .00 .00 .00 .03 .08 .11 .17 .21 .30 .34 .49 .60 .72 .85 .87

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