Please compute on excel

Normal butane is to be isomerised to isobutane in a PFR. For this example, the reaction is elementary and not reversible (ie neglect equilibrium). The "new" specific reaction rate constant of 10h1 was re-measured at 380K after a students data was found to be erroneous. The feed for this reactor will enter at 330K and will use an existing reactor of 6m3. It will process 200kmol/hr of a mixture of 40% butane and 60%N2. Plot the conversion X and reactor Temperature along the reactor using an assumed constant ambient temperature Ta of 25C and a overall heat transfer constant Ua of 2kJ/h.K Additional information: Hrxn=9000J/mol butane (ie. Exothermic), Activation energy 50 kJ/mol Concentration butane0 =15kmol/m3 CPbutane =141J/mol.K, CPi-butane =151J/mol.K, CP N2 =29.14J/mol.K Normal butane is to be isomerised to isobutane in a PFR. For this example, the reaction is elementary and not reversible (ie neglect equilibrium). The "new" specific reaction rate constant of 10h1 was re-measured at 380K after a students data was found to be erroneous. The feed for this reactor will enter at 330K and will use an existing reactor of 6m3. It will process 200kmol/hr of a mixture of 40% butane and 60%N2. Plot the conversion X and reactor Temperature along the reactor using an assumed constant ambient temperature Ta of 25C and a overall heat transfer constant Ua of 2kJ/h.K Additional information: Hrxn=9000J/mol butane (ie. Exothermic), Activation energy 50 kJ/mol Concentration butane0 =15kmol/m3 CPbutane =141J/mol.K, CPi-butane =151J/mol.K, CP N2 =29.14J/mol.K