Question: Please correct my answers if it's wrong and provide a solution. note its thermodynamices problem Cylinders A and B are connected by a thin pipeline

Please correct my answers if it's wrong and provide a solution. noteits thermodynamices problem Cylinders A and B are connected by a thinpipeline with a valve as shown in the figure. The valve isPlease correct my answers if it's wrong and provide a solution. note its thermodynamices problem

Cylinders A and B are connected by a thin pipeline with a valve as shown in the figure. The valve is open and the system is at equilibrium. Cylinder A contains water and gasoline separated by a frictionless piston with a mass of mp=150kg. Cylinder B contains a layer of water on the bottom with a layer of light oil with a mass of moil=182kg on the top. The gasoline in Cylinder A and the oil in Cylinder B are both open to atmospheric conditions at P0=100kPa. Refer to the figure for values of the fluid heights and cylinder cross sectional areas. You may use the properties of light oil and water given in Table A.4. a) Determine the average specific volume of the light oil and water (combined) in Cylinder B,vB. 7 Marks) b) Determine the pressure in the water at the valve location, Pvalve.. 6 Marks) c) Determine the height of the water in Cylinder A,hW,A.(7 Marks) PGasotimePGasolinePwater=P0+gh:100,000+7509.810.2m=101471.5Paof101.4715kPa=Pcuasoline+Amg+g(hwA+1)=101471.5+0.31509.81+0.4979.81(g=(hwaA+1) We don't have the hwa hight I think the quest means only the fight side Rightsideh=AV0.50.2=0.4PLoil=P0+Phh100103+9109.8104=103570.84RaPwatef=PLoil+Pg103570.87+9979.81(0.55+1.5)=123,621.0385aPtePlept=124kPa a) V=meightoil+mwaterVlistoil+Vwater= V=AhVewater=0.550.5=0.275m3/V=m910182=0.2M=PxVmaswater=9970.275=271.175kg/moil=182kgV=2711.175+182(0.2+0.275)m3=0.0010413mg/kg

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