Please deliver a perfect table or diagram if needed. Solve this matter without delay. BJ$20$

$"-$r $$ x $()$

$-$rA $=0\mathrm{.}16(1-$ xA$)(3-$ xA$)$

$-$rA $=0\mathrm{.}4(1-$ xA$)2$

$-$rA $=0\mathrm{.}4(1-$ xA$)(3-$ xA$)$

$-$rA $=0\mathrm{.}48(1-$ xA$)2.-$ A$+$B$=2$C$+$D $$: $-$r

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Rx

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$=8\mathrm{.}134$ kJ$/$molA$$ k $($T $=400$

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K$)=1\mathrm{.}0/$ mol$$sec$.$ A $0\mathrm{.}4$ mol$/$liter $$ B $$ A $.100-$ CSTR $400.$

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K$.."$